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-30x+108=-2x^2
We move all terms to the left:
-30x+108-(-2x^2)=0
We get rid of parentheses
2x^2-30x+108=0
a = 2; b = -30; c = +108;
Δ = b2-4ac
Δ = -302-4·2·108
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6}{2*2}=\frac{24}{4} =6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6}{2*2}=\frac{36}{4} =9 $
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